# How do you graph y = sqrt (3x) + 4 by plotting point?

Oct 7, 2017

$y = \sqrt{3 x} + 4$
graph{sqrt(3x)+4 [-10.38, 9.62, -5, 5]}

$y = \sqrt{3} x + 4$
graph{sqrt3x+4 [-10.38, 9.62, -5, 5]}

#### Explanation:

1) If given equation is $y = \sqrt{3 x} + 4$
$x = 0 , y = 4$
$x = 1 , y = \sqrt{3} + 4$
$x = 2 , y = \sqrt{6} + 4$
$x = 3 , y = 7$
Four points are $\left(0 , 4\right) , \left(1 , 5.732\right) , \left(2 , 6.449\right) , \left(3 , 7\right)$

2) If given equation is $y = \sqrt{3} \cdot x + 4$
Giving values for x, find corresponding value of y from the above equation and plot in a graph.
$x = 0 , y = 4$
$x = 1 , y = \sqrt{3} + 4$
$x = 2 , y = 2 \sqrt{3} + 4$
$x = - 1 , y = - \sqrt{3} + 4$
Four points are $\left(0 , 4\right) , \left(1 , 5.732\right) , \left(2 , 7.464\right) , \left(- 1 , 2.268\right)$