How do you graph #y=sqrt(x+1)# and compare it to the parent graph?

1 Answer
Feb 25, 2018

See explanation

Explanation:

First begin by graphing the parent graph: #y=sqrtx#
graph{sqrtx [-10, 10, -5, 5]}
Now to graph #y=sqrt(x+1)#, let us take a look at the transformation rules concerning #y=sqrtx#.

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As we can see, the #+1# inside the radical implies a horizontal translation or shift. That means that we take each point on the parent graph and shift them #1# unit to the left.

The resulting graph is then...

graph{sqrt(x+1) [-10, 10, -5, 5]}