How do you graph #y = sqrt(x + 2)#?
1 Answer
Apr 29, 2017
see explanation
Explanation:
#sqrt(x+2)>=0# We can plot some coordinate points by choosing key values for x.
#x=-2toy=sqrt0=0rArr(-2,0)#
#x=2toy=sqrt4=2rArr(2,2)#
#x=7toy=sqrt9=3rArr(7,3)# Plot these 3 points and draw a smooth curve through them.
graph{sqrt(x+2) [-10, 10, -5, 5]}
