# How do you graph y=sqrt(x+4)?

Jun 20, 2015

You get hal parabola but along the x axis...have a look:

#### Explanation:

First of all you need to discover the allowed $x$ values for your function, the domain .
The square root can accept all $x$ as long as its argument doesn't get negative (you cannot find a real number as solution of a negative square root). You need all the $x$ such that:
$x + 4 \ge 0$ or:
$x \ge - 4$
Your domain is then all the x bigger or equal to $- 4$:

Next we choose "good" values for $x$ to be used into our function (are good because they allow to evaluate the square root easily):

$x = - 4$ then $y = \sqrt{0} = 0$
$x = - 3$ then $y = \sqrt{1} = 1$
$x = 0$ then $y = \sqrt{4} = 2$
$x = 5$ then $y = \sqrt{9} = 3$
$x = 12$ then #y=sqrt(16)=4

Plotting these points you get: