# How do you graph y=(x+10)/(x^2+5) using asymptotes, intercepts, end behavior?

Nov 5, 2016

The horizontal asymptote is $y = 0$
A point is $\left(0 , 2\right)$

#### Explanation:

The domain of $y$ is $\mathbb{R}$
When $x = 0$ $\implies$ $y = 2$
limit y$= \frac{x}{x} ^ 2 = \frac{1}{x} = 0$
$x \to + \infty$
So a horizontal asymptote is $y = 0$
graph{(x+10)/(x^2+5) [-10, 10, -5, 5]}