How do you graph #y=x^2+2#?

1 Answer
Jul 18, 2015

graph{x^2+2 [-10, 10, -5, 5]}


This is a transformation of a parabola along the y-axis;

#y=x^2# is a parabola with vertex at (0,0). It looks like this:
graph{x^2 [-10, 10, -5, 5]}

#y=x^2+2# is a parabola shifted/transated two units upwards since 2 is being added to the whole equation. The vertex is at (0,2) now.
graph{x^2+2 [-10, 10, -5, 5]}

You can always plug in values to plot if you'e unsure about the rules of transformations, but they are summarized below. Here we had +2 to y so the graph shifted up.