How do you graph #y=x^2 + 4x + 3#?

1 Answer
Aug 11, 2015

The curve is concave upwards.

Explanation:

It is a quadratic function.
It has one turning point. Your graph must include that.
#x^2# has a positive sign. The curve is concave upwards. It has a minimum.
x = #(-b)/(2a)# = #(-4)/(2 xx 1)#= -2

At x = -2 the curve turns. Take a few points on either side of '-2'.
-5, -4, -3, -2, -1, 0, 1 - This is the range of values.

Find the corresponding y co-ordinates.

Plot the points and connect the points with a smooth line.

Refer the pictureenter image source here