How do you graph #y=x^2 + 4x + 3#?
The curve is concave upwards.
It is a quadratic function.
It has one turning point. Your graph must include that.
At x = -2 the curve turns. Take a few points on either side of '-2'.
-5, -4, -3, -2, -1, 0, 1 - This is the range of values.
Find the corresponding y co-ordinates.
Plot the points and connect the points with a smooth line.
Refer the picture