# How do you graph #y=x^2- 6x+2#?

##### 1 Answer

May 22, 2018

vertex =

#### Explanation:

your function is in the form:

From this we can derive:

y-intercept = c

y-int = 2

x-intercept(s) if they exist are the solutions or roots:

Roots (found with the quadratic formula):

axis of symmetry is:

vertex is:

*this means you put the aos value back into the function as x and solve for y.

vertex is:

vertex is:

Finally here is your graph:

graph{x^2- 6x+2 [-9.84, 10.16, -7.48, 2.52]}