How do you graph #y=(x^2-7x-60)/(x+3)# using asymptotes, intercepts, end behavior?
1 Answer
Nov 7, 2016
See the graph below
Explanation:
As you cannot divide by
As the degree of the numerator
So
When
graph{(y-(x^2-7x-60)/(x+3))(y-x+10)=0 [-83.3, 83.26, -41.65, 41.7]}