How do you graph #y<=-x+2# on the coordinate plane?
1 Answer
Oct 18, 2017
See a solution process below:
Explanation:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
For:
We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.
graph{(x^2+(y-2)^2-0.025)((x-2)^2+y^2-0.025)(x+y-2)=0 [-10, 10, -5, 5]}
Now, we can shade the left side of the line.
graph{(x+y-2) <= 0 [-10, 10, -5, 5]}