Question

How do you graph `y=(x+3)^2+4`?

Answer 1

See below.

Explanation:

This equation is in vertex form, where `(h,k)` is the vertex.

Hence,

Vertex ( -3 , 4 )

When `x=0`,

`y=3^2+4`
`color(white)(y)=13`

Y-intercept ( 0 , 13 )

When `x=-6` ( choose any point you want )

`y=(-3)^2+4`
`color(white)(y)=13`

( -6 , 13 )

Plot these three points and connect with a smooth curve and you should get something like this:

Graph:

graph{(x+3)^2-4 [-10, 10, -5, 5]}