# How do you identify all asymptotes or holes for #f(x)=(x^2-9)/(3x+3)#?

##### 1 Answer

#### Explanation:

Asymptotes of algebraic expressions are easy to find,

First of all **vertical asymptotes**, if denominator has a zero at a point but numerator does not have, we have an asymptote at that point.

In the given expression, as denominator is

As regards **horizontal asymptote**, we have it, if the degree of numerator and denominator is equal, but this is not so. Hence, there is no horizontal asymptote.

If the degree of numerator is just one higher than that of denominator, say they are given by

Here the degree of numerator is

Hence

graph{(x^2-9)/(3x+3) [-15, 17, -7.5, 7.5]}