# How do you identity if the equation #y+4=(x-2)^2# is a parabola, circle, ellipse, or hyperbola and how do you graph it?

##### 1 Answer

Feb 7, 2017

#### Answer:

The given equation is a Parabola

#### Explanation:

Given -

#(y+4)=(x-2)^2#

Let us rewrite the equation in a know form

#y+4=x^2-4x+4#

#ycancel (+4)-x^2-4xcancel(-4)=0#

#-x^2-4x+y=0#

Let us have the coics section equation

#Ax^2+Cy^2+Dx+Ey+F=0#

If the product of the coefficient of

In the given equation there is no

The given equation is a Parabola.