How do you integrate #cos(5x)dx#?
1 Answer
Mar 26, 2018
Let
#I = int 1/5cos(u) du#
#I = 1/5sin(u) + C#
#I = 1/5sin(5x) + C#
Hopefully this helps!
Let
#I = int 1/5cos(u) du#
#I = 1/5sin(u) + C#
#I = 1/5sin(5x) + C#
Hopefully this helps!