Question

How do you integrate `e^sqrt(z) /sqrt(z) dz`?

Answer 1

`2 e^sqrt z +C`

Explanation:

Use `(sqrt z)'=1/2(1/sqrtz)`

Here,

`int e^sqrt z/sqrt z dz`

`=2 int e^sqrt z (sqrt z)' dz`

`=2 int e^sqrt z d(sqrt z)`

`=2 e^sqrt z+C`