How do you integrate #int cosx/(1-cos^2x)dx#?
1 Answer
Dec 6, 2016
The integral is
Explanation:
Rewrite
#=>int((cosx)/(sin^2x))dx#
We use the identities
#=>int(cotxcscx)dx#
Use the famous integral that
#=>-cscx + C#
Hopefully this helps!