Question

How do you integrate `int e^(-2x)dx` from `[0,1]`?

Answer 1

In general `int(e^(alphax))dx = 1/alphae^(alphax)`

Explanation:

`int_0^1e^(-2x)dx = -1/2e^(-2x)|_0^1=-1/2 (e^-2-1)`