How do you integrate #int e^(-2x)dx# from #[0,1]#?

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Nov 28, 2016

Answer:

In general #int(e^(alphax))dx = 1/alphae^(alphax)#

Explanation:

#int_0^1e^(-2x)dx = -1/2e^(-2x)|_0^1=-1/2 (e^-2-1)#

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