How do you integrate #int (sec^2theta-sintheta)d theta#?

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Answer 1 · 2017-01-04T03:33:50

It is recommended that you know the following table of trig integrals by heart.

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Separating the integrals:

#=int(sec^2theta)d theta - int(sin theta) d theta#

#= tan theta - (-costheta) d#

#= tan theta + costheta + C#

Hopefully this helps!