How do you integrate ∫x√16+x4dx using trigonometric substitution?
1 Answer
May 19, 2018
Use the substitution
Explanation:
Let
I=∫x√16+x4dx
Apply the substitution
I=12∫dθ
The integral is trivial:
I=12θ+C
Reverse the substitution:
I=12tan−1(x24)+C