Question

How do you integrate `(tanx/secx) dx`?

Answer 1

The integral is `y = -cosx+ C`.

Explanation:

Start by simplifying the function using the identities `tantheta = sintheta/costheta` and `sectheta = 1/costheta`.

`tanx/secx = (sinx/cosx)/(1/cosx) = sinx`

If you know your basic integrals, `int(sinx)dx = -cosx + C`.

Hopefully this helps!