Question

How do you integrate `y=(-7x^4)^(8/5)`?

Answer 1

`-35/37x^(37/5)+c`

Explanation:

Require to use `color(blue)"power rule for integration"`

`int(ax^n)=a/(n+1)x^(n+1)`

`rArrint(-7x^4)^(8/5)dx=int-7x^(32/5)dx`

applying the power rule.

`rArrint-7x^(32/5)dx=(-7)/(37/5)x^(37/5)+c=-35/37x^(37/5)+c`

where c is the constant of integration.