How do you make a table to graph #f(x)=(1/2)^(x -3)#?

1 Answer
Dec 29, 2015

#f(x)=(1/2)^(x-3)#
Put #x=-2 implies f(-2)=(1/2)^(-2-3)=(1/2)^-5=(2)^5=32#
#implies f(-2)=32#
Put #x=-1 implies f(-1)=(1/2)^(-1-3)=(1/2)^-4=(2)^4=16#
#implies f(-1)=16#
Put #x=0 implies f(0)=(1/2)^(0-3)=(1/2)^-3=(2)^3=8#
#implies f(0)=8#
Put #x=1 implies f(1)=(1/2)^(1-3)=(1/2)^-2=(2)^2=4#
#implies f(1)=4#
Put #x=2 implies f(2)=(1/2)^(2-3)=(1/2)^-1=(2)^1=2#
#implies f(2)=2#
Put #x=3 implies f(3)=(1/2)^(3-3)=(1/2)^0=(2)^0=1#
#implies f(3)=1#

Now plot these values on graph paper and you will get the curve of the equation.