How do you multiply #-0.2i(16+8i)#?
1 Answer
Jul 25, 2016
1.6 - 3.2i
Explanation:
Distribute the bracket in the 'usual' way.
#rArr-0.2i(16+8i)=(-0.2ixx16)+(-0.2ixx8i)#
#=-3.2i-1.6i^2#
#color(orange)"Reminder "color(red)(|bar(ul(color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#rArr-0.2i(16+8i)=-3.2i-1.6(-1)=1.6-3.2i#
