How do you multiply (2-2x)^4?

1 Answer
Oct 25, 2015

16x^4 + 48x^2+16x+16

Explanation:

(2-2x)^4=(2 - 2x)(2 - 2x)(2 - 2x)(2 - 2x)
You should separate them into two, you must use FOIL, (first, outside, inside, last)

(4x^2-4x+4)(4x^2-4x+4)

Do it again!

(4x^2*4x^2)+ (4x^2* -4x)+(4x^2*4)+(-4x*4x^2)+(-4x*-4x) + (-4x*4) + (4*4x^2)+(4*-4x)+(4*4)

16x^4 - 16x^3 + 16x^2 - 16x^3 + 16x^2 - 16x +16x^2 - 16x + 16

16x^4 + 48x^2 + 16x + 16

It's a very long and boring problem which can probably be simplified with some rule.