How do you multiply #(2+4i)(3+3i)#?

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Answer 1 · 2016-08-17T08:55:10

#-6+18i#.

The Expressiom#=(2+4i)(3+3i)=(2(1+2i))(3(1+i))#

#=6(1+2i)(1+i)#

#=6{1(1+i)+2i(1+i)}#

#=6{1+i+2i+2i^2}#

#=6{1+3i+2(-1)}#

#=6(-1+3i)#

#=-6+18i#.