How do you multiply #(2-6i)(7+7i)(3+3i)#?

1 Answer
Jim G.
Feb 20, 2017

#252+84i#

Explanation:

Multiply the first 2 factors and then multiply the result by the third factor.

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(2/2)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(2/2)|)))#

Using the FOIL method to distribute.

#rArr(2-6i)(7+7i)#

#=14+14i-42i-42i^2#

#=56-28i#

Now multiply this product by the third factor.

#rArr(56-28i)(3+3i)#

#=168+168i-84i-84i^2#

#=252+84i#

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