How do you multiply #(2b-1)(b^2-3b+4)#?

1 Answer
Jun 26, 2018

Answer:

#color(red)(2b^3-4b^2+11b-4)#

Explanation:

#color(magenta)(""(2b-1))(b^2-3b+4)#

using the distributive property:
#color(white)("XXX")=color(magenta)(2b)(b^2-3b+4)color(white)("xxxx")color(magenta)(-1)(b^2-3b+4)#

#color(white)("XXX")=2b^3-3b^2+8bcolor(white)("xxxx)-b^2+3b-4#

combining like terms:
#color(white)("XXX")=2b^3-4b^2+11b-4#