How do you multiply #(2c - 3) ( 4c - 3)#?

2 Answers
Apr 9, 2018

Answer:

#8c^2-18c+9#

Explanation:

To multiply these two parentheses you have to FOIL

This means to multiply the FIRST two values in each

Then multiply the OUTSIDE two values in each

Then multiply the INSIDE two values in each

Then multiply the LAST two values in each

First:
#2c*4c = 8c^2#

Outside:
#2c*(-3) =-6c#

Inside:
#-3 * 4c=-12c#

Last:
#-3*-3=9#

Now combine all the terms:

#8c^2-6c-12c+9#

Now combine like terms:

#8c^2-18c+9#

Answer:

#8c^2-6c-12c+9#

Explanation:

You multiply the first two terms #(2c xx 4c)#, then the outer terms #(2c xx (-3))#, then the inner terms #(-3 xx 4c)#, then the last 2 terms #(2c xx (-3))#.