# How do you multiply 2m^2(2m^2+3m-5)?

Oct 11, 2016

$4 {m}^{4} + 6 {m}^{3} - {10}^{2}$

#### Explanation:

Distribute the term outside of the set of parenthesis to each term on the inside of the parenthesis.

So, start with the first term in the parenthesis: $2 {m}^{2}$

Distribute $2 {m}^{2}$ to $2 {m}^{2}$ and multiply
$2 {m}^{2} \times 2 {m}^{2} = 4 {m}^{4}$

Next distribute $2 {m}^{2}$ to the second term in the parenthesis: $3 m$

$2 {m}^{2} \times 3 m = 6 {m}^{3}$

Lastly, distribute $2 {m}^{2}$ to the third and final term in the parenthesis: $- 5$

$2 m 62 \times - 5 = - 10 {m}^{2}$

So, the equation would look like:
$4 {m}^{4} + 6 {m}^{3} - {10}^{2}$

I just expanded it so you could see each individual step