How do you multiply #(2t + 3)(3t - 5)#?

1 Answer
May 18, 2018

Answer:

#6t^2-t-15#

Explanation:

#"each term in the second bracket is multiplied by each"#
#"term in the first bracket"#

#rArr(color(red)(2t+3))(3t-5)#

#=color(red)(2t)(3t-5)color(red)(+3)(3t-5)larrcolor(blue)"distribute"#

#=(color(red)(2t)xx3t)+(color(red)(2t)xx-5)+(color(red)(3)xx3t)+(color(red)(3)xx-5)#

#=6t^2color(magenta)(-10t)color(magenta)(+9t)-15larrcolor(blue)"collect like terms"#

#=6t^2-t-15#