How do you multiply #(2x+2)(5x-3)#?

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Answer 1 · 2017-01-30T05:59:10

See the entire solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(2x) + color(red)(2))(color(blue)(5x) - color(blue)(3))# becomes:

#(color(red)(2x) xx color(blue)(5x)) - (color(red)(2x) xx color(blue)(3)) + (color(red)(2) xx color(blue)(5x)) - (color(red)(2) xx color(blue)(3))#

#10x^2 - 6x + 10x - 6#

We can now combine like terms:

#10x^2 + (-6 + 10)x - 6#

#10x^2 + 4x - 6#