# How do you multiply (3+2i) (2-i)?

Feb 11, 2016

This is $\left(8 + i\right)$.

#### Explanation:

This can be multiplied just like any other binomial * binomial:
FOIL.

so we have $\left(6 + 4 i - 3 i - 2 {i}^{2}\right)$

Since ${i}^{2} = - 1$, the last term is equal to $+ 2$

So we have $\left(6 + 4 i - 3 i + 2\right)$

Combine like terms and get the answer $\left(8 + i\right)$