How do you multiply (3-2i)(5-6i)? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Karthik G Jan 14, 2016 Steps are given below. Explanation: (3-2i)(5-6i) Use FOIL =(3)(5) + (3)(-6i) - (2i)(5) + (-2i)(-6i) =15 - 18i - 10i + 12i^2 color(red) "note : i² =-1" =15 -28i + 12(-1) =15-28i-12 =3-28i Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square (1+i)? What is the geometric interpretation of multiplying two complex numbers? What is the product of 3+2i and 1+7i? How do I use DeMoivre's theorem to solve z^3-1=0? How do I find the product of two imaginary numbers? How do you simplify (2+4i)(2-4i)? How do you multiply (-2-8i)(6+7i)? See all questions in Multiplication of Complex Numbers Impact of this question 4704 views around the world You can reuse this answer Creative Commons License