How do you multiply #(-3-7i)(-12-2i)#?
1 Answer
Feb 12, 2018
Explanation:
#"note "i^2=(sqrt(-1))^2=-1#
#"expand using FOIL and collect like terms"#
#rArr(-3-7i)(-12-2i)#
#=36+6i+84i+14i^2#
#=36+90i-14#
#=22+90ilarrcolor(red)"in standard form"#
