How do you multiply $(3 i) (- 2 + 6 i)$ $(3i)(-2+6i)$ ?

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Answer 1 · 2016-08-19T15:57:58

-6i-18

i is the imaginary number $\sqrt{-} 1$ $sqrt-1$
So 3x ( $\sqrt{-} 1$ $sqrt-1$ )x -2 = -6x ( $\sqrt{-} 1$ $sqrt-1$ )=-6i

3x ( $\sqrt{-} 1$ $sqrt-1$ )x 6 x ( $\sqrt{-} 1$ $sqrt-1$ ) =18 x-1

=-18

Answer. -6i -18

How do you multiply (3i)(−2+6i)(3i)(-2+6i)?