How do you multiply $(3x+1)(x-2)$ ?

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Answer 1 · 2015-07-04T03:38:09

Multiply each term in one factor time each term in the other factor

We need to multiply: $3x$ times $x$ and times $-2$ and we need to multiply $1$ times $x$ and times $-2$ .

We can (but are not required to) write:

$(3x+1)(x-2) = (3x*x) + (3x * -2) + (1*x)+ (1*-2)$

We get:

$(3x+1)(x-2) = 3x^2 + (-6x) + x+ (-2)$

which is also equal to
$(3x+1)(x-2) = 3x^2 -6x + x -2$

Now simplify by combining like terms ( $-6x+x = -5x$ )

$(3x+1)(x-2) = 3x^2 -5x -2$

How do you multiply (3x+1)(x-2)(3x+1)(x-2)?