How do you multiply #(-3x^2-1)(-x+9)#?

1 Answer
Jun 30, 2017

Answer:

See a solution process below:

Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(-3x^2) - color(red)(1))(color(blue)(-x) + color(blue)(9))# becomes:

#(color(red)(-3x^2) xx color(blue)(-x)) - (color(red)(3x^2) xx color(blue)(9)) + (color(red)(-1) xx color(blue)(-x)) - (color(red)(1) xx color(blue)(9))#

#3x^3 - 27x^2 + x - 9#