How do you multiply #( 3x^2 + 4y + 2) ( y + 3)#?

1 Answer
Jun 26, 2015

Answer:

# = color(blue)(3x^2y + 4y^2 +9x^2 + 14y + 6#

Explanation:

# (3x^2+4y+2)color(blue)((y+3)#

  • Multiply #color(blue)(y)# with each of the three terms of the first bracket:

# = (3x^2 . color(blue)(y)) + (4y .color(blue)(y)) + (2 . color(blue)(y))#

# = color(blue)(3x^2y + 4y^2 + 2y#..........#(1)#

  • Multiply #color(blue)(3)# with each of the three terms of the first bracket:
    # = (3x^2 . color(blue)(3)) + (4y .color(blue)(3)) + (2 . color(blue)(3))#

# = color(blue)(9x^2 + 12y + 6#...... #(2)#

combining #1# and #2#
# = color(blue)(3x^2y + 4y^2 +9x^2 + 14y + 6#