# How do you multiply (3x^2-5)(x^4-1)?

Jun 29, 2017

See a solution process below:

#### Explanation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$\left(\textcolor{red}{3 {x}^{2}} - \textcolor{red}{5}\right) \left(\textcolor{b l u e}{{x}^{4}} - \textcolor{b l u e}{1}\right)$ becomes:

$\left(\textcolor{red}{3 {x}^{2}} \times \textcolor{b l u e}{{x}^{4}}\right) - \left(\textcolor{red}{3 {x}^{2}} \times \textcolor{b l u e}{1}\right) - \left(\textcolor{red}{5} \times \textcolor{b l u e}{{x}^{4}}\right) + \left(\textcolor{red}{5} \times \textcolor{b l u e}{1}\right)$

$3 {x}^{6} - 3 {x}^{2} - 5 {x}^{4} + 5$

We can put the polynomial in standard form as:

$3 {x}^{6} - 5 {x}^{4} - 3 {x}^{2} + 5$