How do you multiply #4(3x+1) (x-2)#?

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Answer 1 · 2015-04-06T21:14:49

Start by FOILing the two binomials:
#4(3x+1)(x-2)#
#4(3x^2 -6x + x -2)#
#4(3x^2 - 5x -2)#
Distribute the #4# to all the terms:
#12x^2 - 20x -8#