# How do you multiply 4(3x+1) (x-2)?

$4 \left(3 x + 1\right) \left(x - 2\right)$
$4 \left(3 {x}^{2} - 6 x + x - 2\right)$
$4 \left(3 {x}^{2} - 5 x - 2\right)$
Distribute the $4$ to all the terms:
$12 {x}^{2} - 20 x - 8$