How do you multiply #(-4m^2-3n)^2#?

1 Answer
Aug 21, 2017

Answer:

See a solution process below:

Explanation:

We can use this rule to multiply this expression:

#(color(red)(x) + color(blue)(y))^2 = color(red)(x)^2 + 2color(red)(x)color(blue)(y) + color(blue)(y)^2#

Substituting #color(red)(-4m^2)# for color(red)(x) and substituting #color(blue)(-3n)# for #color(blue)(y)# gives:

#(color(red)(-4m^2) + color(blue)(-3n))^2 =>#

#color(red)((-4m^2))^2 + (2 * color(red)(-4m^2) * color(blue)(-3n)) + color(blue)((-3n))^2 =>#

#16m^4 + 24m^2n + 9n^2#