How do you multiply #(4u-1)^2#?

1 Answer
Jan 16, 2017

Answer:

#16u^2-8u+1#

Explanation:

We can express #(4u-1)^2" as " (4u-1)(4u-1)#

We must ensure that each term in the second bracket is multiplied by each term in the first bracket.This is illustrated as follows.

#(color(red)(4u-1))(4u-1)#

#=color(red)(4u)(4u-1)color(red)(-1)(4u-1)#

distributing the brackets.

#16u^2-4u-4u+1#

collecting like terms.

#=16u^2-8u+1#