# How do you multiply (4u-1)^2?

Jan 16, 2017

$16 {u}^{2} - 8 u + 1$

#### Explanation:

We can express ${\left(4 u - 1\right)}^{2} \text{ as } \left(4 u - 1\right) \left(4 u - 1\right)$

We must ensure that each term in the second bracket is multiplied by each term in the first bracket.This is illustrated as follows.

$\left(\textcolor{red}{4 u - 1}\right) \left(4 u - 1\right)$

$= \textcolor{red}{4 u} \left(4 u - 1\right) \textcolor{red}{- 1} \left(4 u - 1\right)$

distributing the brackets.

$16 {u}^{2} - 4 u - 4 u + 1$

collecting like terms.

$= 16 {u}^{2} - 8 u + 1$