How do you multiply #4x(3x^2+2x+1) #?

1 Answer
Jun 24, 2015

Answer:

# = color(blue)( 12x^3 + 8x^2 +4x#

Explanation:

#color(blue)(4x)(3x^2 + 2x +1)#
Here # color(blue)(4x)# needs to be multiplied with each term within bracket:

#=color(blue)(4x) . (3x^2 ) + color(blue)(4x).(2x) +color(blue)(4x).(1) #
# = color(blue)( 12x^3 + 8x^2 +4x#