How do you multiply #(5x-1/3)^2#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer EZ as pi Jun 21, 2016 #=25x^2 -(10x)/3 + 1/9# Explanation: Multiply the bracket by itself: There will be 4 terms. #(5x - 1/3)^2 = (5x - 1/3)(5x - 1/3)# #= 25x^2 -(5x)/3 - (5x)/3 + 1/9# #=25x^2 -(10x)/3 + 1/9# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1378 views around the world You can reuse this answer Creative Commons License