How do you multiply #(5y+3)(4y^2-7y-2)#?

1 Answer
Dec 14, 2016

Answer:

#20y^3-23y^2-31y-6#

Explanation:

We must ensure that each term in the second bracket is multiplied by each term in the first bracket.

#rArr(color(red)(5y+3))(4y^2-7y-2)#

#=color(red)(5y)(4y^2-7y-2)color(red)(+3)(4y^2-7y-2)#

#"now distribute the brackets"#

#=20y^3-35y^2-10y+12y^2-21y-6#

#"collecting like terms gives"#

#=20y^3+y^2(-35+12)+y(-10-21)-6#

#=20y^3-23y^2-31y-6#