How do you multiply #(6-3i)(3-i)#?
1 Answer
Sep 12, 2016
Explanation:
distribute the brackets using, for example, the FOIL method.
#rArr(6-3i)(3-i)=18-6i-9i+3i^2=18-15i+3i^2#
#color(orange)"Reminder " #
#color(red)(bar(ul(|color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#rArr18-15i+3i^2=18-15i-3=15-15i#
#rArr(6-3i)(3-i)=15-15i#