How do you multiply $(6 - 3 i) (3 - i)$ $(6-3i)(3-i)$ ?

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How do you multiply $(6 - 3 i) (3 - i)$ $(6-3i)(3-i)$ ?

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Answer 1 · 2016-09-12T18:40:53

$15 - 15 i$ $15-15i$

Explanation:

distribute the brackets using, for example, the FOIL method.

$\Rightarrow (6 - 3 i) (3 - i) = 18 - 6 i - 9 i + 3 i^{2} = 18 - 15 i + 3 i^{2}$ $rArr(6-3i)(3-i)=18-6i-9i+3i^2=18-15i+3i^2$

$Reminder$ $color(orange)"Reminder "$

$color(red)(bar(ul(|color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))$

$rArr18-15i+3i^2=18-15i-3=15-15i$

$rArr(6-3i)(3-i)=15-15i$

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How do you multiply $(6 - 3 i) (3 - i)$ $(6-3i)(3-i)$ ?

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