# How do you multiply (6x-3) (4x+33)?

Dec 14, 2016

$24 {x}^{2} + 186 x - 99$

#### Explanation:

You need to cross multiply each term in the parenthesis on the left by each term in the parenthesis on the right and then group like terms:

$\left(6 x \cdot 4 x\right) + \left(6 x \cdot 33\right) - \left(3 \cdot 4 x\right) - \left(3 \cdot 33\right)$

$24 {x}^{2} + 198 x - 12 x - 99$

$24 {x}^{2} + \left(198 - 12\right) x - 99$

$24 {x}^{2} + 186 x - 99$