How do you multiply #(6x-3) (4x+33)#?

1 Answer
Dec 14, 2016

Answer:

#24x^2 + 186x - 99#

Explanation:

You need to cross multiply each term in the parenthesis on the left by each term in the parenthesis on the right and then group like terms:

#(6x*4x) + (6x*33) - (3*4x) - (3*33)#

#24x^2 + 198x - 12x - 99#

#24x^2 + (198 - 12)x - 99#

#24x^2 + 186x - 99#