How do you multiply #(7+3i)(-7+5i)(-8-4i)#?

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Jim G. Share
Mar 9, 2018

Answer:

#568+144i#

Explanation:

#"multiply any pair of factors using FOIL and then"#
#"multiply the result by the third remaining factor"#

#color(orange)"Reminder"color(white)(x)i^2=(sqrt(-1))^2=-1#

#rArr(7+3i)(-7+5i)#

#=-49+14i+15i^2=14i-64#

#rArr(14i-64)(-8-4i)#

#=-112i-56i^2+512+256i#

#=568+144i#

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