# How do you multiply (8n+1) (6n-3)?

Jul 17, 2015

$= 48 {n}^{2} - 18 n - 3$

#### Explanation:

$\textcolor{b l u e}{\left(8 n + 1\right)} \left(6 n - 3\right)$
Here, both the terms of color(blue)((8n+1) need to be multiplied with both of the terms of $\left(6 n - 3\right)$

$= \textcolor{b l u e}{\left(8 n\right)} \left(6 n\right) + \textcolor{b l u e}{\left(8 n\right)} \left(- 3\right) + \textcolor{b l u e}{1} \left(6 n\right) + \textcolor{b l u e}{1} \left(- 3\right)$

$= 48 {n}^{2} - 24 n + 6 n - 3$

$= 48 {n}^{2} - 18 n - 3$