How do you multiply #(8n+1) (6n-3)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Don't Memorise Jul 17, 2015 #=48n^2 -18n -3# Explanation: #color(blue)((8n+1))(6n-3)# Here, both the terms of #color(blue)((8n+1)# need to be multiplied with both of the terms of #(6n-3)# #=color(blue)((8n))(6n) +color(blue)((8n))(-3) + color(blue)(1)(6n)+ color(blue)(1)(-3)# #=48n^2 -24n +6n-3# #=48n^2 -18n -3# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 2248 views around the world You can reuse this answer Creative Commons License