How do you multiply $(8n+1) (6n-3)$ ?

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Answer 1 · 2015-07-17T07:09:01

$=48n^2 -18n -3$

$color(blue)((8n+1))(6n-3)$
Here, both the terms of $color(blue)((8n+1)$ need to be multiplied with both of the terms of $(6n-3)$

$=color(blue)((8n))(6n) +color(blue)((8n))(-3) + color(blue)(1)(6n)+ color(blue)(1)(-3)$

$=48n^2 -24n +6n-3$

$=48n^2 -18n -3$

How do you multiply (8n+1) (6n-3)(8n+1) (6n-3)?