# How do you multiply (8p-2)(6p+2) ?

Jul 11, 2015

$\left(8 p - 2\right) \left(6 p + 2\right) = 48 {p}^{2} + 4 p - 4$

#### Explanation:

Use the FOIL method which indicates the order in which the terms of each binomial are multiplied.

$\left(8 p - 2\right) \left(6 p + 2\right)$ =

$\left(8 p \cdot 6 p\right) + \left(8 p \cdot 2\right) + \left(- 2 \cdot 6 p\right) + \left(- 2 \cdot 2\right)$ =

$48 {p}^{2} + 16 p - 12 p - 4$ =

$48 {p}^{2} + 4 p - 4$